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Somerhing´s not correct
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Luis A. Afonso  
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 More options Jul 2, 7:41 am
Newsgroups: sci.stat.math
From: "Luis A. Afonso" <lic...@hotmail.com>
Date: Wed, 01 Jul 2009 17:41:23 EDT
Local: Thurs, Jul 2 2009 7:41 am
Subject: Somerhing´s not correct
Something´s not correct

San josé State University:
www.applet-magic.com/samplemin.htm
it can be read:
******** If p(x) is the probability density function for a random variable x, let P(x) be the cumulative probability function; i.e.,
P(x) = Intg(-infinity, x).p(z)dz
The probability that the minimum of a sample of size n is x is given by
Prob.(min size n sample) = n[1- P(x)]^(n-1) * p(x)
*********************************************
My comment
Suppose, for example,
Uniform [0, 1] Distribution, P(x) = x, p(x) =1
Prob.(min size n sample) = 21[1- x]^20 * 1
If x=0.05 then results 7.528,
This is, no doubt, a remarkable thing (!!!). The Applet is so magic that it not available yet. Please, remove it!
The writer did intend to say:
____Prob (min <=x) = 1- (1-F(x))^n
____1- (1-0.05)^21=0.659438______
Simulation (data 8E6 items) gave 0.660, 0.660.
Prob (absolute deviation > 0.0005 | N=8E6) <=
2*EXP(-2*8E6*0.25*1E-6) = 2*EXP(-4) = 0.037= 3.7%
(According to Dvorestky - Kiefer - Wolfowitz inequality, states).
REM "ckontas"
        CLS
        DEFDBL A-Z
        DIM x(22)
        INPUT " x=  "; x0
        p = 1 - (1 - x0) ^ 21
        PRINT USING "#.### "; p
        all = 8000000
        RANDOMIZE TIMER
        FOR j = 1 TO all
        LOCATE 4, 4: PRINT USING "########"; all - j
        minor = 8
        FOR i = 1 TO 21
        x = RND
        IF x < minor THEN minor = x
        NEXT i
        IF minor > x0 THEN GOTO 10
        okk = okk + 1
10      NEXT j: LOCATE 10, 10
        PRINT USING "#.### "; okk / all
        END

Luis A. Afonso


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Henry  
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 More options Jul 2, 11:03 am
Newsgroups: sci.stat.math
From: Henry <s...@btinternet.com>
Date: Thu, 02 Jul 2009 02:03:10 +0100
Local: Thurs, Jul 2 2009 11:03 am
Subject: Re: Somerhing´s not correct

For a continuous random variable, the probability that the minimum of a
sample of size n is exactly x is given by 0.

What the author probably intended to say was that the probability
*density* of the minimum of a sample of size n is x is given by
f(min size n sample) = n[1- P(x)]^(n-1) * p(x)

There is nothing remarkable about a probability density being more than
1.  Note that the integral of f(x) dx with P(x) = x, p(x)=1 from x=0 to
0.05 is indeed about 0.659438..., which hardly needs 8000000 runs round
a simulation to calculate.


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Luis A. Afonso  
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 More options Jul 2, 1:09 pm
Newsgroups: sci.stat.math
From: "Luis A. Afonso" <lic...@hotmail.com>
Date: Wed, 01 Jul 2009 23:09:21 EDT
Local: Thurs, Jul 2 2009 1:09 pm
Subject: Re: Somerhing´s not correct
Date: Jul 1, 2009 9:03 PM
Author: Henry
Subject: Re: Somerhing´s not correct

Luis A. Afonso wrote: > Something´s not correct

 San José State University:

www.applet-magic.com/samplemin.htm> it can be read:

******** If p(x) is the probability density function for a random variable x, let P(x) be the cumulative probability function; i.e.,
 P(x) = Intg(-infinity, x).p(z)dz

 The probability that the minimum of a sample of size n is x is given by
Prob.(min size n sample) = n[1- P(x)]^(n-1) * p(x)

 *********************************************

My comment

Suppose, for example,

 Uniform [0, 1] Distribution, P(x) = x, p(x) =1
 Prob.(min size n sample) = 21[1- x]^20 * 1
 If x=0.05 then results 7.528,
This is, no doubt, a remarkable thing (!!!). The Applet is so magic that it not available yet. Please, remove it! The writer did intend to say:
 ____Prob (min <=x) = 1- (1-F(x))^n

 ____1- (1-0.05)^21=0.659438______
For a continuous random variable, the probability that the minimum of a sample of size n is exactly x is given by 0. What the author probably intended to say was that the probability *density* of the minimum of a sample of size n is x is given by f(min size n sample) = n[1- P(x)]^(n-1) * p(x) There is nothing remarkable about a probability density being more than 1.
Note that the integral of f(x) dx with P(x) = x, p(x)=1 from x=0 to 0.05 is indeed about 0.659438...,
which hardly needs 8000000 runs round a simulation to calculate.

******************************

My response

__1__You agree, it´s evident, that the *genius* that posted such a thing should be severely adverted by the University.
__2__You are sufficiently smart to understand that the simulation is an addendum to the formula, or not?
__3__Your opinion what the author *intended to say* is a simple and unintelligent extrapolation. Doing so you think, in your *naivety*, people will to absolve him. Furthermore it was him (not me) that gave the formula of the probability of the minimum be x:  you should correct him as long as he published the post.
__4__Aspiring you to be known as a scrupulous person in Statistics, why you didn’t correct the error your fellow barbarous countryman got?. That was YOUR task.

Luis A. Afonso


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Henry  
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 More options Jul 2, 6:20 pm
Newsgroups: sci.stat.math
From: Henry <s...@btinternet.com>
Date: Thu, 2 Jul 2009 01:20:57 -0700 (PDT)
Local: Thurs, Jul 2 2009 6:20 pm
Subject: Re: Somerhing´s not correct
On 2 July, 04:09, "Luis A. Afonso" <lic...@hotmail.com> wrote:

> __3__Your opinion what the author *intended to say* is a simple and unintelligent extrapolation.

You are correct to say it is simple, but wrong to say unintelligent or
extrapolation, since it only involves inserting a single word used in
the same context on the same page, rather than integrating a formula.

Sometimes you worry too much about others, and your ability to be
polite often seems to be a couple of slices of bread short of a
sandwich.  Your "Somerhing" was not a word, but I am not at all
concerned about it, because it is obviously a typing error replacing t
by the adjacent r.


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